- #1

- 529

- 2

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter fonseh
- Start date

- #1

- 529

- 2

- #2

Chestermiller

Mentor

- 21,631

- 4,912

$$\frac{k}{\mu}v=\frac{h}{H_2}\gamma_w$$Therefore, substituting this into the additional contribution of seepage flow to the pore pressure at C, we obtain ##\frac{h}{H_2}z\gamma_w##. Therefore, the total pore pressure at C is $$(H+z)\gamma_w+\frac{h}{H_2}z\gamma_w=\left(H+z+\frac{h}{H_2}z\right)\gamma_w$$

- #3

- 529

- 2

I have another example here . In this case , it's

$$\frac{k}{\mu}v=\frac{h}{H_2}\gamma_w$$Therefore, substituting this into the additional contribution of seepage flow to the pore pressure at C, we obtain ##\frac{h}{H_2}z\gamma_w##. Therefore, the total pore pressure at C is $$(H+z)\gamma_w+\frac{h}{H_2}z\gamma_w=\left(H+z+\frac{h}{H_2}z\right)\gamma_w$$

- #4

Chestermiller

Mentor

- 21,631

- 4,912

- #5

- 529

- 2

so , do you mean as the water flow from top to the bottom , so the water is saying to be flow from higher pressure to low pressure ? So , in the case of downwards seepage , the pressure at A > C >B ?

- #6

Chestermiller

Mentor

- 21,631

- 4,912

Only the viscous seepage portion of the pressure variation, which superimposes linearly upon the hydrostatic portion of the pressure variation, to give the overall total pressure variation.so , do you mean as the water flow from top to the bottom , so the water is saying to be flow from higher pressure to low pressure ? So , in the case of downwards seepage , the pressure at A > C >B ?

- #7

- 529

- 2

So , the pressure due to seepage variation is A > C >B ??Only the viscous seepage portion of the pressure variation, which superimposes linearly upon the hydrostatic portion of the pressure variation, to give the overall total pressure variation.

- #8

Chestermiller

Mentor

- 21,631

- 4,912

Yes, if the flow is downward.So , the pressure due to seepage variation is A > C >B ??

- #9

- 529

- 2

Can you explain what causes The additional contribution of seepage flow to the pore pressure at C is ##\frac{k}{\mu}vz## ?? Is there any name for the term ?

$$\frac{k}{\mu}v=\frac{h}{H_2}\gamma_w$$Therefore, substituting this into the additional contribution of seepage flow to the pore pressure at C, we obtain ##\frac{h}{H_2}z\gamma_w##. Therefore, the total pore pressure at C is $$(H+z)\gamma_w+\frac{h}{H_2}z\gamma_w=\left(H+z+\frac{h}{H_2}z\right)\gamma_w$$

- #10

Chestermiller

Mentor

- 21,631

- 4,912

The differential equation for the variation of pressure in a porous medium (in the vertical direction) is $$\frac{dp}{dz}+\gamma=-\frac{k}{\mu}v$$ where, in this equation, z is the elevation and v is the superficial upward seepage velocity. This is Darcy's Law.Can you explain what causes The additional contribution of seepage flow to the pore pressure at C is ##\frac{k}{\mu}vz## ?? Is there any name for the term ?

Share: