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## Homework Statement

An isolated conductor of thickness 'a' is placed between the plates of a parallel plate capacitor. Find the capacitance

## Homework Equations

C = A/(4*pi*d)

## The Attempt at a Solution

C1 = A/(4*pi*((d-a)/2))

C2 = A/(4*pi*((d-a)/2))

1/C = 1/C1 + 1/C2

Plugging in C1 and C2...

1/C = (8*pi*((d-a)/2)) / A

or

C = A / (8*pi*((d-a)/2)

If im understanding this correctly...the conductor divides the capacitor into two capacitors in series...if someone can confirm this i appreciate it. TIA.